Python L1 Assignments - Top Coder

Python L1 Assignments:

Here we are going to list Python L1 Assignments questions with answers you can see the solution and learn from it.

Happy Learning !!

What will be the output of ‘seclist’ in print commands of below code?

mylist = range(4)

seclist = mylist

print seclist

mylist.append(4)

print seclist

seclist = mylist[:]

print seclist

mylist.append(5)

print seclist

Answer:

[0,1,2,3]

[0,1,2,3,4]

[0,1,2,3,4]

[0,1,2,3,4]

What is the output of following code:

def f(n):

for x in range(n):

yield x**3

for x in f(6):

print (x)

Answer:

0 1 8 27 64 125

Write a program to receive a string fromkeybordand check if the string has two ‘e’ in the characters. If yes return True else False.

Answer:

c=raw_input(“”)

n=c.count(“e”,0,len(c))

if n==2:

print “True”

else:

print “False”

What is the output of following code:

counter = 1

def dolots(count):

global counter

for i in (1, 2, 3):

counter = count + i

print dolots(4)

print counter

Answer:

7

5. Write a code to read the data from input file called input.txt and count the number of characters per line, number of words per line and write these into output file called as output.txt

Answer :

fname = “input.txt”

oFname = “output.txt”

num_words = 0

num_chars = 0

with open(fname, ‘r’) as f:

with open(oFname, ‘w’) as f1:

for line in f:

words = line.split()

f1.writelines(‘%d’ %len(words))

f1.writelines(‘\n’);

f1.writelines(‘%d’ %len(line))

f1.writelines(‘\n’);

6. Create 3 Lists ( list1,list2,list3) with numbers and perform following operations

1. a) CreateMaxlist by taking 2 maximum elements from each list.
2. b) Find average value from all the elements ofMaxlist.
3. c) Create aMinlIst by taking 2 minimum elements from each list
4. d) Find the average value from all the elements ofMinlist

Answer :

list1=range(10,20)

list2=range(30,40)

list3=range(50,60)

list1.sort()

list2.sort()

list3.sort()

minList=[]

maxList=[]

minList=[list1[0],list1[1],list2[0],list2[1],list3[0],list3[1]]

maxList=[list1[len(list1)-2],list1[len(list1)-1],list2[len(list2)-2],list2[len(list2)-1],list3[len(list3)-2],list3[len(list3)-1]]

print sum(minList) / float(len(minList))

print sum(maxList) / float(len(maxList))

7. Write program to convert prefix/net mask to IP. eg: input:16 output: 255.255.0.0

Answer:

import socket

import struct

host_bits = 32 – int(16)

netmask = socket.inet_ntoa(struct.pack(‘!I’, (1 << 32) – (1 << host_bits)))

print netmask

8. Create a suitable data construct to read the data from an xml document as shown below:

<title lang=”en“>Everyday Italian</title>

<author>Giada De Laurentiis</author>

</book>

<title lang=”en“>Harry Potter</title>

<author>J K. Rowling</author>

</book>

<title lang=”en“>Learning XML</title>

</book>

</bookstore>

Answer:

import xml.etree.ElementTree as ET

tree = ET.parse(‘BookXML.xml’)

root = tree.getroot()

count=0

count1=0

for child in root:

print “\n”

print “Name :”+root[count1][0].text

print “Author :”+root[count1][1].text

print “Year :”+root[count1][2].text

print “\n”

count1+=1

9. Create a suitable object type and check for file size of 0 bytes of the directory contents as shown below

02/15/2016 10:49 PM 962 switchfinal.py

02/15/2016 10:49 PM 943 switchfinal.py.bak

01/27/2016 11:46 AM 15 t.py

03/31/2016 12:39 PM 840 t1.py

01/25/2016 10:34 AM 2,407 tc1.py

02/14/2017 09:13 AM 0 teat.py

03/15/2016 05:52 PM 5 tes.py

Answer:

import os

basedir = ‘C:/Py‘

count=0

names = os.listdir(basedir)

sizes = [(path, os.stat(path).st_size) for path in names]

for size in sizes:

if size[1]==0:

count+=1

if count==0:

print “No file with zero size”

else:

print “There are files with zero size”