Hacker Rank Problem
Given a positive integer denoting , do the following:
- If , then print the lowercase English word corresponding to the number (e.g.,
onefor ,twofor , etc.). - If , print
Greater than 9.
Input Format
A single integer denoting .
Constraints
Output Format
If , then print the lowercase English word corresponding to the number (e.g.,
one for , two for , etc.); otherwise, print Greater than 9 instead.Sample Input 0
5
Sample Output 0
five
Explanation 0
five is the English word for the number .Sample Input 1
8
Sample Output 1
eight
Explanation 1
eight is the English word for the number .Sample Input 2
44
Sample Output 2
Greater than 9
Explanation 2
is greater than , so we print
Greater than 9.Hacker Rank Problem Solution
| #include <iostream> #include <cstdio> using namespace std; // Sumit Kumar int main() { | |
| int N; | |
| cin >> N; | |
| if (N == 1) { | |
| cout << “one“ << endl; | |
| } else if (N == 2) { | |
| cout << “two“ << endl; | |
| } else if (N == 3) { | |
| cout << “three“ << endl; | |
| } else if (N == 4) { | |
| cout << “four“ << endl; | |
| } else if (N == 5) { | |
| cout << “five“ << endl; | |
| } else if (N == 6) { | |
| cout << “six“ << endl; | |
| } else if (N == 7) { | |
| cout << “seven“ << endl; | |
| } else if (N == 8) { | |
| cout << “eight“ << endl; | |
| } else if (N == 9) { | |
| cout << “nine“ << endl; | |
| } else { | |
| cout << “Greater than 9“ << endl; | |
| } return 0; |
}
